Can we insert data in view? how can we insert data into a view mcq.
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This is because variables in Java do not follow polymorphism and overriding is only applicable to methods, not variables. And when an instance variable in a child class has the same name as an instance variable in a parent class, then the instance variable is chosen from the reference type.
Q) Which cannot be inherited from a base class in Java programming. Constructor of a class cannot be inherited. But note that they can be invoked from a derived class. final method can be inherited just they cannot be overridden in sub class.
Inheritance of Variables. The hierarchy of the Smalltalk language is designed such that the subclasses inherit the variables of its superclass. Subclasses can also add variables of its own. Class and instance variables are added to the class by placing them in the class definition.
I know that instance variable are not inherited but they can be accessed in sub class. If they can be accessed in sub class then does that means that they are shared between super class and subclass or both super class and subclass have different copy.
Private Members in a Superclass A subclass does not inherit the private members of its parent class. However, if the superclass has public or protected methods for accessing its private fields, these can also be used by the subclass.
Static methods cannot be overridden because they are not dispatched on the object instance at runtime. The compiler decides which method gets called.
12 Answers. In simple words, a constructor cannot be inherited, since in subclasses it has a different name (the name of the subclass). Methods, instead, are inherited with “the same name” and can be used.
Explanation: Final class cannot be inherited.
Constructors are not normal methods and they cannot be “overridden”. Saying that a constructor can be overridden would imply that a superclass constructor would be visible and could be called to create an instance of a subclass.
Java supports only Single, Multilevel, and Hierarchical types of inheritance. Java does not support Multiple and Hybrid inheritance.
inheritence and polymorphism doesnt apply for instance fields. they are only visible in your sub-class if they are marked protected or public. currently you have super class variable marked private. no other class can access it.
To prevent inheritance, use the keyword “final” when creating the class. The designers of the String class realized that it was not a candidate for inheritance and have prevented it from being extended.
Yes. A java private member cannot be inherited as it is available only to the declared java class. Since the private members cannot be inherited, there is no place for discussion on java runtime overloading or java overriding (polymorphism) features.
No, a constructor can’t be made final. A final method cannot be overridden by any subclasses. As mentioned previously, the final modifier prevents a method from being modified in a subclass. … In other words, constructors cannot be inherited in Java therefore, there is no need to write final before constructors.
The main purpose of using a class being declared as final is to prevent the class from being subclassed. … If a class is marked as final then no class can inherit any feature from the final class.
A class cannot extend itself since it IS itself, so it is not a subclass. Inner classes are allowed to extend the outer class because those are two different classes.
Yes, overloading a final method is perfectly legitimate.
Yes, you can overload main method in Java. But the program doesn’t execute the overloaded main method when you run your program, you have to call the overloaded main method from the actual main method. that means main method acts as an entry point for the java interpreter to start the execute of the application.
No, the Methods that are declared as final cannot be Overridden or hidden.
A static constructor doesn’t take access modifiers or have parameters. A class or struct can only have one static constructor. Static constructors cannot be inherited or overloaded. A static constructor cannot be called directly and is only meant to be called by the common language runtime (CLR).
Inheritance in Java is a mechanism in which one object acquires all the properties and behaviors of a parent object. It is an important part of OOPs (Object Oriented programming system). The idea behind inheritance in Java is that you can create new classes that are built upon existing classes.
To declare (create) a variable, you will specify the type, leave at least one space, then the name for the variable and end the line with a semicolon ( ; ). Java uses the keyword int for integer, double for a floating point number (a double precision number), and boolean for a Boolean value (true or false).
Java final keyword is a non-access specifier that is used to restrict a class, variable, and method. If we initialize a variable with the final keyword, then we cannot modify its value. If we declare a method as final, then it cannot be overridden by any subclasses.
The @Override annotation is one of a default Java annotation and it can be introduced in Java 1.5 Version. … It extracts a warning from the compiler if the annotated method doesn’t actually override anything. It can improve the readability of the source code.
Yes. Class can have private constructor. Even abstract class can have private constructor. By making constructor private, we prevent the class from being instantiated as well as subclassing of that class.
Static methods in Java are inherited, but can not be overridden. If you declare the same method in a subclass, you hide the superclass method instead of overriding it. Static methods are not polymorphic. At the compile time, the static method will be statically linked.
The reason behind this is to prevent ambiguity. Consider a case where class B extends class A and Class C and both class A and C have the same method display(). Now java compiler cannot decide, which display method it should inherit. To prevent such situation, multiple inheritances is not allowed in java.
Java supports multiple inheritance through interfaces only. A class can implement any number of interfaces but can extend only one class. Multiple inheritance is not supported because it leads to deadly diamond problem.
Answer: Abstraction shields the implementation details and encapsulation hides the object details. The object is the abstract form of the real-world and its details are hidden using encapsulation. Thus encapsulation is required for abstraction.
Can we override a static method? No, we cannot override static methods because method overriding is based on dynamic binding at runtime and the static methods are bonded using static binding at compile time. So, we cannot override static methods.
The second class is unable to inherit the first class. … We achieve this functionality by calling the appropriate super() method in Java, that should map to appropriate super class constructor. If you do not provide a default constructor, than JDK compiler will insert a default super constructor call in your constructor.
The only difference between a normal variable and a final variable is that we can re-assign the value to a normal variable but we cannot change the value of a final variable once assigned. Hence final variables must be used only for the values that we want to remain constant throughout the execution of the program.
A subclass within the same package as the instance’s superclass can override any superclass method that is not declared private or final. A subclass in a different package can only override the non-final methods declared public or protected.
Yes, We can overload the main method in java but JVM only calls the original main method, it will never call our overloaded main method.
Abstraction by it self is possible without inheritance: You can make a class abstract and it does not require any inheritance.
No, we cannot override private or static methods in Java. Private methods in Java are not visible to any other class which limits their scope to the class in which they are declared.